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Answer:
So, there are 3 cards in total, which means your pobability of picking one card out of the 3 cards is %33.33. So the probability of picking a 7 is 1/3. Because the other two numbers are greater than 7, and you already picked 7 so you cannot pick it again, the probabitily of pick a number greater than 7 is %100, or 3/3.
I hope that answers your question! :)
The probability of picking a 7 and then picking a number greater than 7 is [tex]\dfrac{1}{3}[/tex] or [tex]0.\overline{3}[/tex].
Probability
Probability shows us the chances of an event occurring.
[tex]\bold{Probability =\dfrac{Desired\ Outcome}{Total\ number\ of\ outcomes\ possible}}[/tex]
Now, given that we have already picked three cards. therefore, 7, 8, and 9.
The number of possible outcomes is 3.
the probability of card 7,
[tex]\bold{Probability(7) =\dfrac{Number\ 7(1)}{Total\ number\ of\ outcomes\ possible (3)}= \dfrac{1}{3}}[/tex]
Now, as card seven is already picked up cards 8 and 9 are the only card left.
therefore, the sample size(possible outcomes) was reduced to 2 only.
Also, cards 8 and 9 both are greater than 7, thus the desired outcome is also 2.
Further the probability of the number greater than 7 occurring,
[tex]\bold{Probability(n>7) =\dfrac{cards\ 8\ and\ 9(2)}{Total\ number\ of\ outcomes\ possible (2)}= \dfrac{2}{2} = 1}[/tex]
Probability picking a number greater than 7
The probability of picking a 7 and then picking a number greater than 7
= Probability of card 7 occuring x probability of card 8 and 9 occurring
[tex]=\dfrac{1}{3}\times 1[/tex]
[tex]=\dfrac{1}{3}[/tex]
Hence, the probability of picking a 7 and then picking a number greater than 7 is [tex]\dfrac{1}{3}[/tex] or [tex]0.\overline{3}[/tex].
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