A current of 23.0 mA is maintained in a single circular loop with a circumference of 1.50 m. A magnetic field of 0.310 T is directed parallel to the plane of the loop. What is the magnitude of the torque exerted by the magnetic field on the loop?

Respuesta :

Answer:

0 Nm

Explanation:

The magnetic dipole moment, μ, is the product of the current and the area of the loop.

[tex]\mu = IA[/tex]

The torque is given by

[tex]\tau = \mu B\sin\theta[/tex]

where B is the magnetic field and θ is the angle between the field and the loop.

From the question, the field is parallel to the plane of the loop. Hence,

θ = 0°.

[tex]\tau = \mu B\sin0^\circ = 0 \text{ Nm}[/tex]

Answer: The magnitude of torque is 1.28Nm

Explanation: Please see the attachments below

Ver imagen Abdulazeez10
Ver imagen Abdulazeez10