answer-
he should mix 16lbs of the 7.80 mix and 8lbs of the 11.40 mix
Step-by-step explanation:
hope this helps:) btw im a student at rsm and i got this for homework so ya. your welcome also, ik the answers wrong ...s i g h...
Answer:
The merchant should mix 53.33 pounds of cheaper cacao and 26.67 pounds of costlier cacao.
Step-by-step explanation:
A merchant wants to blend 80 pounds of cacao worth $9.00 a pound from two kinds: one at $11.40 a pound and the other at $7.80 a pound.
Let the number of pounds of cheaper cacao be x
Let the number of pounds of costlier cacao be y
The merchant wants total pounds = 80
So, first equation becomes:
[tex]x+y=80[/tex] or [tex]x=80-y[/tex]
Now values of per pounds become [tex]7.80x[/tex] and [tex]11.40y[/tex]
As the merchant wants the mixture worth $9 so second equation becomes:
[tex]7.80x+11.40y=9(80)[/tex]
=> [tex]7.80x+11.40y=720[/tex]
Substituting [tex]x=80-y[/tex] in second equation, we get
[tex]7.80(80-y)+11.40y=720[/tex]
=> [tex]624-7.80y+11.40y=720[/tex]
=> [tex]3.60y=96[/tex]
[tex]y=26.67[/tex] pounds
We know, [tex]x=80-y[/tex]
=> [tex]x=53.33[/tex] pounds
So, The merchant should mix 53.33 pounds of cheaper cacao and 26.67 pounds of costlier cacao.
We can check this:
[tex]53.33(7.80)+26.67(11.40)=720.012[/tex] dollars
