Answer:
[tex]1.79\ m^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the triangular prism is equal to
[tex]SA=2B+PL[/tex]
where
B is the area of the triangular base
P is the perimeter of the triangular base
L is the length of the prism
Find the area of the triangular base B
[tex]B=\frac{1}{2}(0.8)(0.1)=0.04\ m^{2}[/tex]
Find the perimeter of the triangular base P
[tex]P=(0.8+0.1+0.81)=1.71\ m[/tex]
we have
[tex]L=1\ m[/tex]
substitute the values and find the surface area
[tex]SA=2(0.04)+(1.71)*(1)=1.79\ m^{2}[/tex]
