Answer:
[tex]\large\boxed{y=0.6x-3.2}[/tex]
Step-by-step explanation:
The slope-intercept form:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have
[tex]y=0.6x+3[/tex]
Parallel lines have the same slope. Therefore we have the equation:
[tex]y=0.6x+b[/tex]
The line passes through the point (-3, -5). Put the coordinates of the point to the equation and solve it for b:
[tex]-5=0.6(-3)+b[/tex]
[tex]-5=-1.8+b[/tex] add 1.8 to both sides
[tex]-3.2=b[/tex]
Finally we have:
[tex]y=0.6x-3.2[/tex]
