Answer:
5.00 is the value of the initial balance (i.e. when time is 0) in the savings account.
Step-by-step explanation:
We have the function, [tex]f(x)=5.00(1.012}^x[/tex] which represents the balance in the savings account.
Now, if we substitute x= 0, we have,
[tex]f(x)=5.00(1.012}^x[/tex] implies [tex]f(0)=5.00(1.012}^0[/tex]
As, 'any number with power 0 is equal to 1 i.e. [tex]x^0=1[/tex]'.
We get,
[tex]f(0)=5.00(1.012}^0[/tex] implies [tex]f(0)=5.00\times 1[/tex] i.e. f(0)= 5.00
Thus, we see that,
5.00 is the value of the initial balance (i.e. when time is 0) in the savings account.
