AC+CE=AE
Pythagorean theorem is a big part of this problem. a^2+b^2=c^2
Part AC
8^2+6^2=c^2
64+36= 100
c^2 =
[tex] \sqrt{100} [/tex]
or
5^2 to match c^2.
Part CE
It is similar to the other one. It's just scaled. 6 to 8, 4 to....6
4^2+6^2=c^2
16+36=52
[tex] \sqrt{52} [/tex]
It is not a perfect square. So that will be the answer.
Answer:
Step-by-step explanation:
The short side of AB is 2 units shorter than BC.
Side DE has to be 2 units longer than side CD, which is 6.
AE will be the sum of 6 + 8 + 4 + 6, which is 24.
