Answer:
1000 Joules per second.
Explanation:
To lift that much grass 5 meters higher than it was before the tractor did work that is the product of the (force needed to overdo gravity) and (displacement):
[tex]W = mg\Delta h=120kg\cdot 10\frac{m}{s^2}\cdot 5m = 6000J[/tex]
Power is work over the amount of time:
[tex]P = \frac{W}{\Delta t}=\frac{6000J}{6 s} = 1000 \frac{J}{s}[/tex]
