ΔABC is similar to ΔDEF. The length of segment AC is 12 cm. The length of segment BC is 18 cm. The length of segment DF is 10 cm.

What is the length of segment EF?
Question 1 options:


15


14


10


9

Respuesta :

5naka

since similar, then

EF/BC = DF/AC

EF = BC•DF/AC

= 18•10/12

= 15

Similar triangles may or may not be congruent.

The value of EF is 15.

[tex]\mathbf{ABC \sim \triangle DE F}[/tex] means that:

[tex]\mathbf{AB \sim D E}[/tex]

[tex]\mathbf{BC \sim EF}[/tex]

[tex]\mathbf{AC \sim DF}[/tex]

So, the equivalent ratio is:

[tex]\mathbf{EF:BC = DF:AC}[/tex]

Where:

[tex]\mathbf{BC = 18, DF = 10, AC = 12}[/tex]

Substitute these values in [tex]\mathbf{EF:BC = DF:AC}[/tex]

[tex]\mathbf{EF:18 = 10:12}[/tex]

Express as fractions

[tex]\mathbf{\frac{EF}{18} = \frac{10}{12}}[/tex]

Multiply both sides by 18

[tex]\mathbf{EF = \frac{10}{12} \times 18}[/tex]

Simplify

[tex]\mathbf{EF = \frac{10}{2} \times 3}[/tex]

[tex]\mathbf{EF = 5 \times 3}[/tex]

[tex]\mathbf{EF = 15}[/tex]

Hence, the value of EF is 15.

Read more about similar triangles at:

https://brainly.com/question/14926756