Answer : The type of bond present in [tex]Sr_3(PO_4)_2[/tex] is, ionic bond.
Explanation :
Ionic bond : It is defined as the bond that is formed by complete transfer of electrons from one atom to another atom.
That means, the atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom.
The ionic bond is usually formed between a metal and a non-metal.
Covalent bond : It is defined as the bond which is formed when sharing of electrons takes place between the atoms.
This is usually formed between two non-metals.
As we know that the strontium is the alkali metal having the atomic number 38 and belongs to group 2. The symbol of strontium is, (Sr). The stable oxidation state of strontium is (+2).
The element phosphate is the non-metal polyatomic ion. The stable oxidation state of phosphate ion [tex](PO_4^{3-})[/tex] is, (-3).
When the strontium combine with the phosphate ion, it forms strontium phosphate. It is an ionic compound in which the a metal react with the non-metal and combine with the an ionic bond by the criss-cross method. Thus, the formula of the strontium phosphate is, [tex]Sr_3(PO_4)_2[/tex]
Hence, the type of bond present in [tex]Sr_3(PO_4)_2[/tex] is, ionic bond.
