Respuesta :
Heat energy released here
Q = mass x specific heat capacity of water x deltaT
= 25.0 x 4.184 x (-10.0)
= - 1046 Joules
1046 Joules of heat energy is released in this process.
Answer: The amount of heat released is -1046 J
Explanation:
To calculate the amount of heat released, we use the equation:
[tex]q=mc\Delta T[/tex]
where,
q = heat released = ?
m = mass of water = 25.0 g
c = specific heat capacity of water = 4.184 J/g.°C
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(10.0-20.0)^oC=-10.0^oC[/tex]
Putting values in above equation, we get:
[tex]q=25.0g\times 4.184J/g.^oC\times (-10.0^oC)\\\\q=-1046J[/tex]
Hence, the amount of heat released is -1046 J
