A scientist digs up sample of arctic ice that is 458,000 years old. He takes it to his lab and finds that it contains 1.675 grams of krypton-81. If the half-life of krypton-81 is 229,000 years, how much krypton-81 was present when the ice first formed? Use the formula N = N0 . The ice originally contained grams of krypton 81.

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Answer:

6.70 g

Explanation:

A common formula for determining the amount of sample remaining in terms of its half-life is

[tex]N =N_{0}(\frac{ 1}{2 })^{n}[/tex]

where

[tex]n = \frac{t }{t_{\frac{1 }{2 }} }[/tex]

t = 458 000 yr

[tex]t_{\frac{1}{2} = \text{229 000 yr}[/tex]         Calculate n

n = 458 000/229 000

n = 2.000

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N = 1.675 g                       Calculate N₀

[tex]1.675 = N_{0}(\frac{ 1}{2 })^{2.000}[/tex]

1.675 = N₀ × 0.2500     Divide by 0.2500 and transpose

N₀ = 1.675/0.2500

N₀ = 6.70 g

The correct answer is

6.70

:)