Use Pythagorean theorem, and calculate the diameter of the base.
d- diameter
[tex]d^2+9.5^2=19.3^2\\\\d^2+90.25=372.49\qquad\text{subtract 90.25 from both sides}\\\\d^2=282.24\to d=\sqrt{282.24}\\\\d=16.8\ m[/tex]
r - radius
d = 2r → 2r = 16.8 → r = 8.4 m
The fromula of a volume of a cylinder:
[tex]V=\pi r^2h[/tex]
Substitute r = 8.4 m and h = 9.5 m:
[tex]V=\pi\cdot8.4^2\cdot9.5=670.32\pi\ m^3[/tex]
