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According to the fundamental theorem of algebra, how many zeros does the function f(x) = 4x3 - x2 - 2x + 1 have?

A) 1
B)2
C)3
D)4

Respuesta :

Hello from MrBillDoesMath!


Answer   C)     (or 3 )


Discussion:  f(x) is an equation of degree 3 as the highest exponent of "x" is the number 3.   The fundamental theorem tell us there are 3 zeroes or roots but not about their character (e.g. are they all real? real and complex?)


Regards, MrB.

Answer: c)3 roots

Step-by-step explanation:

According to the fundamental theorem of algebra, any polynomial expression of degree n has n roots.

So, in this case:

f(x) = 4x3 - x2 - 2x + 1

The degree of the polynomial expression is given by the highest exponent on a variable. The term that has the highest exponent is 4x∧3.

Since the degree of the polynomial is 3, it has 3 roots.

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