alisoncevallosp0v236 alisoncevallosp0v236

15-10-2018
Mathematics

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The circle x^2+y^2=4 has the point _ as its center

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Ammimochi Ammimochi

15-10-2018

Center (0,0)

Radius: 2

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prayag11 prayag11

15-10-2018

HEY THERE!!

Compare the above equation with
[tex]( {x}^{2} - h)( {y}^{2} - k) = {r}^{2} \\ \\ so \: here \: h = and \: k = 0 \\ so \: the \: centre \: is \: (0 \: 0) \: and \: the \: radius \: is \: 2[/tex]
Hope it helped you.

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