Respuesta :
Answer: The theoretical yield of titanium (IV) chloride is 853.56 grams.
Explanation:
We are given:
Moles of titanium metal = 5.00 mole
Moles of chlorine gas = 9.00 mole
The chemical equation for the reaction of titanium and chlorine gas follows:
[tex]Ti+2Cl_2\rightarrow TiCl_4[/tex]
By Stoichiometry of the reaction:
2 moles of chlorine gas reacts with 1 mole of titanium metal.
So, 9 moles of chlorine gas will react with = [tex]\frac{1}{2}\times 9=4.5mol[/tex] of titanium metal.
As, given amount of titanium metal is more than the required amount. So, it is considered as an excess reagent.
Thus, chlorine gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of chlorine gas produces 1 mole of titanium (IV) chloride.
So, 9 moles of chlorine gas will produce = [tex]\frac{1}{2}\times 9=4.5moles[/tex] of titanium (IV) chloride.
To calculate the mass from given number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of titanium (IV) chloride = 189.68 g/mol
Moles of titanium (IV) chloride = 4.5 moles
Putting values in above equation, we get:
[tex]4.5mol=\frac{\text{Mass of titanium (IV) chloride}}{189.68g/mol}\\\\\text{Mass of titanium (IV) chloride}=(4.5mol\times 189.68g/mol)=853.56g[/tex]
Hence, the theoretical yield of titanium (IV) chloride is 853.56 grams.
