Answer: 6.6 moles of aluminium
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 molecule of [tex]Al_2Si_4O_{10}(OH)_2[/tex] contains = 2 atoms of aluminium
1 mole of [tex]Al_2Si_4O_{10}(OH)_2[/tex] contains = 2 moles of aluminium
Thus 3.30 moles of [tex]Al_2Si_4O_{10}(OH)_2[/tex] contain =[tex]\frac{2}{1]\times 3.30=6.6[/tex] moles of aluminium
Thus there are 6.6 moles of aluminium in the given compound.
