to find the x-intercept of any equation, we simply set y = 0, and then solve for "x".
[tex]\bf \stackrel{f(x)}{0}=\cfrac{2}{3}x+4\implies -4=\cfrac{2x}{3}\implies -12=2x\implies \cfrac{-12}{2}=x\implies -6=x
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\rule{34em}{0.25pt}\\\\
~\hfill \stackrel{x-intercept}{(-6,0)}~\hfill[/tex]
now to find the y-intercept....hmmm wait just a second, the equation is already in slope-intercept form, therefore,
[tex]\bf \begin{array}{|c|ll}
\cline{1-1}
slope-intercept~form\\
\cline{1-1}
\\
y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}}
\\\\
\cline{1-1}
\end{array}~\hspace{7em}f(x)=\stackrel{slope}{\cfrac{2}{3}}x+\stackrel{y-intercept}{4}
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\rule{34em}{0.25pt}\\\\
~\hfill \stackrel{y-intercept}{(0,4)}~\hfill[/tex]
