SOLUTION IS
WE KNOW STANDARD EQUATION OF CIRCLE[tex][tex](X-a)^{2}[/tex]+[tex](Y-b)^{2}[/tex]=[tex]r^{2}[/tex]
where (a,b) is centre and r is radius of circle
now we have to find component of centre and radius
we know centre of circle is equidistance from end points of diameter
apply formula to find mid point of line( (x1+x2)/2,(y1+y2)/2) we get
((x-x)/2,(y-y)/2)=(0,0)
hence component of circle is (0,0)
now apply distance formula between (0,0)and (x,y)
we get [tex]x^{2}[/tex]+[tex]y^{2}[/tex]=[tex]r^{2}[/tex]
hence standard equation of circlre is =[tex]X^{2}[/tex]+[tex]Y^{2}[/tex]=[tex]x^{2}[/tex]+[tex]y^{2}[/tex]
