Answer:
0.3733 L or 373 mL
Solution:
Data Given:
Mass = 8.97 g
M.Mass of (NH₄)₂CO₃ = 96.09 g.mol⁻¹
Molarity = 0.250 mol.L⁻¹
Step 1: Calculate Moles of Ammonium Carbonate as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 8.97 g ÷ 96.09 g.mol⁻¹
Moles = 0.0933 mol
Step 2: Calculate Volume of Solution as,
Molarity = Moles ÷ Volume
Solving for Volume,
Volume = Mole ÷ Molarity
Putting values,
Volume = 0.0933 mol ÷ 0.250 mol.L⁻¹
Volume = 0.3733 L
Or,
Volume = 373 mL
