Respuesta :
The heat Q can be evaluated as:
Q=mcΔT
where:
m is the mass
c specific heat
ΔT change in temperature.
So:
a)
47=10.7c(25-13)
c=0.39 J/g°C
Using the same idea you get (I transformed g into moles using the molar mass of silver from the table of elements):
b) Q=(10.7/107.9)×25.35×15.2=38.21 J
where: Molar mass of Ag = 107.8682 g/mol
c) 38.21=10.7c15.2
c=specific heat of silver=0.235 J/g°C
Q=mcΔT
where:
m is the mass
c specific heat
ΔT change in temperature.
So:
a)
47=10.7c(25-13)
c=0.39 J/g°C
Using the same idea you get (I transformed g into moles using the molar mass of silver from the table of elements):
b) Q=(10.7/107.9)×25.35×15.2=38.21 J
where: Molar mass of Ag = 107.8682 g/mol
c) 38.21=10.7c15.2
c=specific heat of silver=0.235 J/g°C
Answer:
a) 0.3660 J/g°C is the specific heat for the metal.
b) 37.7 Joules energy would it take to raise the temperature of 10.7 grams of silver by 15.2°C.
c)The specific heat of silver is 0.2347 J/g°C.
Explanation:
Energy required to raise the temperature,Q = 47.0 J
Mass of the unknown metal = m = 10.7 g
Change in temperature = ΔT = 25.0°C - 13.0°C = 12°C
Specific heat of metal = c
[tex]Q=mc\Delta T[/tex]
[tex]47.0 J=10.7 g\times c\times 12^oC[/tex]
[tex]c=\frac{47.0 J}{10.7 g\times 12^oC}=0.3660 J/g^oC[/tex]
0.3660 J/g°C is the specific heat for the metal.
b) The molar heat capacity of silver = [tex]c_m=25.35 J/mol^oC[/tex]
Molar mass of silver ,M= 108 g/mol
Specific heat of silver = c = [tex]\frac{c_m}{M}=-\frac{25.35 J/mol^oC}{108 g/mol}=0.2347 J/g ^oC[/tex]
Given mass of silver = m = 10.7 g
Change in temperature = ΔT = 15°C
Energy required to raise the temperature of silver = Q
[tex]Q=mc\Delta T[/tex]
[tex]Q= 10.7 g\times 0.2347 J/g ^oC\times 15^oC[/tex]
Q = 37.7 Joules
37.7 Joules energy would it take to raise the temperature of 10.7 grams of silver by 15.2°C.
c) The specific heat of silver is calculated in (b) part above.
Specific heat of silver = c = [tex]\frac{c_m}{M}=-\frac{25.35 J/mol^oC}{108 g/mol}=0.2347 J/g ^oC[/tex]