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A cessna 150 airplane has a takeoff speed of 28 m/s. determine the minimum length of the runway which would be required for the plane to take off if it averages an acceleration of 1.9 m/s/s.

Respuesta :

Histrionicus

Given: Takeoff Speed (u) = 28 m/s

Final velocity (v) = 0.0 m/s

Acceleration (a) = 1.9 m/s²

To calculate: The minimum length of runway (s) =?

Solution: Apply 3rd kinematic equation of motion

                                 v² = u² - 2as

Or,                              s =  ( u² -  v²) / 2 a

Or,                              s =  ( 28² - 0²) / 2 × 1.9 m

Or,                              s =  206.3 m

Hence, the required minimum length of the runway will be 206.3 m

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