Mass percentage is given as:
[tex]Mass percentage = \frac{mass of element}{total mass of the compound}\times 100[/tex]%
Let the total mass of protein = 100 g.
Mass percentage of [tex]Mg[/tex] in protein = 0.672%
That means 0.672 g of [tex]Mg[/tex] is present in 100 g of protein.
Atomic mass of [tex]Mg[/tex] = 24.305 u
Number of moles = [tex]\frac{mass}{Molar mass}[/tex]
Number of moles of [tex]Mg[/tex] = [tex]\frac{0.672}{24.305} = 0.028 mol[/tex]
Since, 1 molecule of protein contains 3 atoms of [tex]Mg[/tex] so, moles of protein is:
Moles of protein = [tex]\frac{0.0028}{3} = 0.0093 mol[/tex]
Rearranging the formula of number of moles as:
[tex]Molar mass = \frac{mass}{mole}[/tex]
Substituting the values:
Molar mass of protein = [tex]\frac{100 g}{0.0093 mol}[/tex]
Molar mass of protein = [tex]10752.69 g/mol[/tex]
Hence, the molar mass of metalloprotein is [tex]10752.69 g/mol[/tex].
