The numbers are "x" and "y".
We can suggest this equation:
x+y=56
xy=72
We can solve this equation by substitution method.
x+y=56 ⇒x=56-y
(56-y)y=72
56y-y²=72
y²-56y+72=0
Now, we solve this square equatión:
y=[56⁺₋√(56²-4*1*72)] / 2=(56⁺₋√2848)/2
We have two solutions:
y₁=(56-√2848)/2≈1.3167 ⇒x₁=56-y₁≈54.6833
y₂=(56+√2848)/2≈54,6833 ⇒x₂=56-y₂≈1.3167
Therefore the numbers are 1.3167 and 54.6833
