1. You have that the speed is:
[tex] V=\frac{d}{t} [/tex]
Where [tex] d [/tex] is the distance and [tex] t [/tex] is the time.
2. Tory pilots her boat [tex] 50 km [/tex]before docking, therefore, his time is
[tex] t1=\frac{50km}{V} [/tex]
3. Emilio continues for another [tex] 2 hours [/tex], with a total of [tex] 80 km [/tex] before docking. Therefore, his time is:
[tex] t2=(\frac{50km}{2} +2h) [/tex]
4. And his speed is:
[tex] V=\frac{80km}{(\frac{50km}{V}+2h)} [/tex]
5. Solve for [tex] V [/tex] and substitute the value into the formula of Tory's time:
[tex] \\V=15\frac{km}{h} \\ t1=\frac{50km}{15\frac{km}{h}} t1=3.33h [/tex]
The answer is: [tex] 3.33 hours [/tex]
