1. Draw graphs y=|x-2|-1 and y=2. The first graph is obtained from the graph of the function y=|x| by translating 2 units right and 1 unit down. (see picture)
2. The part of the graph y=|x-2|-1 that lies under the line y=2 is not a solution (then |x-2|-1<2) and the part that lies over the line is a solution (then |x-2|-1>2).
3. Both these graphs intersect at points (-1,2) and (5,2). Since unequality is strong, you can conclude, that
[tex]x\ \textless \ -1 \text{ and } x\ \textgreater \ 5[/tex].
