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Which solution will have a higher boiling point: A solution containing 15 grams of sucrose (C12H22O11) in 25 grams of water or a solution containing 35 grams of sodium chloride in 500 grams of water?

Respuesta :

The answer is sodium chloride solution

Boiling point will increase based on the molality(mol per 1000gram solution) of the solution. The exact value formula should be: T= i * Kb * molality
Kb is the constant of the solvent(water) and i is the Van Hoff factor of the solute.

The molecular mass of sucrose is 342g/mol. The increase of boiling point for sucrose  solution is: 
T= i * Kb * molality
T= i * Kb * mol / (solvent/ 1000g)
T= 1 * Kb * 15grams/(342grams/mol) / (25gram1000g)
T= 1 * Kb * 0.043mol / 0.025
T= 1.7643 Kb

The molecular mass of sodium chloride is 58.5g/mol and its van hoff factor is 2(it dissolve into Na+ and Cl-). The increase of boiling point for sucrose  solution is: 
T= i * Kb * molality
T= i * Kb * mol / 1kg solvent
T= 2 * Kb * 35grams/(58.5g/mol) / (500g/1000g)
T= 2 * Kb * 0.598mol / 0.5
T= 2.3931 Kb