Calculate the freezing point of a 2.1 m aqueous sucrose solution. (assume that kf for water is 1.86∘c/m.)

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13-06-2018
Chemistry

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Calculate the freezing point of a 2.1 m aqueous sucrose solution. (assume that kf for water is 1.86∘c/m.)

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Edufirst Edufirst · Answer 1 · 2018-06-23T04:44:02+02:00

Edufirst Edufirst

23-06-2018

Answer: - 3.91 °C

Explanation:

1) The depression of the freezing point of a solution is a colligative property and its value is:

ΔTf = m × Kf × i

2) i is the Van't Hoof constant ans for non ionic solutes is 1.

3) m is the molality

m = 2.1 m

3) ΔTf = 2.1 m × 1 × 1.86 °C / mol = 3.91°C.

5) Freezing poin (temperature)

Tf = 0° - 3.91 °C = - 3.91°C

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