which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Check all that apply. y = –x + 1 3x − 4y = −4 4x − 3y = −3 y – 2 = –(x – 4) y + 2 = (x + 4)

Respuesta :

Answer:

[tex]\text{The equation represent the line that is parallel to 3x - 4y = 7 and passes through the point (-4, -2) is 3x-4y=-4}[/tex]      

Step-by-step explanation:

Given the equation 3x - 4y = 7

we have to find the equation which represent the line that is parallel to          3x - 4y = 7 and passes through the point (-4, -2)

As parallel lines have same slope therefore we find the slope of given line

[tex]3x-4y=7[/tex]

[tex]4y=3x-7[/tex]

[tex]y=\frac{3}{4}x-\frac{7}{4}[/tex]

Comparing above equation with general equation y=mx+c, where m is slope

⇒ [tex]m=\frac{3}{4}[/tex]

[tex]\text{The equation of line having slope }\frac{3}{4}\text{ and passing through the point (-4,-2) is}[/tex]

[tex]y-y'=m(x-x')[/tex]

[tex]y-(-2)=\frac{3}{4}(x-(-4))[/tex]

[tex]y+2=\frac{3}{4}(x+4)[/tex]

[tex]4y+8=3x+12[/tex]

[tex]3x-4y=-4[/tex]

which is required equation.

Option 2 is correct.