Consider the 1-to10^19 scale on which the disk of the Milky Way Galaxy fits on a football field. On this scale, how far is it from the sun to the alpa centauri (real distance:4.4 light-years) How big is the sun itself on this scale? Compare the sun's size on this scale to the actual size of a typical atom (about 10^-10 m in diameter).

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Limosa

Answer:

Sun is [tex]0.4162708[/tex] cm away from alpha century.

Sun is [tex]1.391016\times10^{-10}[/tex]m.

Sun is 1.391016 time the size of an atom at this scale.

Step-by-step explanation:

Light year is a measure of distance. It is the distance light travels in an year.

Light year = [tex]9.4607\times10^{12}[/tex] km

So 4.4 light years = [tex]4.4\times9.4607\times10^{12}[/tex] km

                                [tex]41.62708\times10^{12}[/tex] km

Lets scale this down to the level of [tex]1\times10^{-19}[/tex]

[tex]41.62708\times10^{12}\times1\times10^{-19}[/tex] km

=[tex]41.62708\times10^{-7}[/tex] km

Change the units to centimeters:

[tex]41.62708\times10^{-7}\times1\times10^{5}[/tex] cm

=[tex]41.62708\times10^{-2}[/tex] cm

=[tex]0.4162708[/tex] cm

Therefore on the new scale sun is [tex]0.4162708[/tex] cm away from alpha century.

Diameter of the sun is 1.391016 million km

Lets change Sun's diameter to the new scale:

[tex]1.391016\times10^{6} \times10^{-19}[/tex]km

=[tex]1.391016\times10^{-13}[/tex]km

Lets change kilometers in to meters:

[tex]1.391016\times10^{-13}\times10^{3}[/tex]m

=[tex]1.391016\times10^{-10}[/tex]m

Therefore, sun is [tex]1.391016\times10^{-10}[/tex]m

and an atom is [tex]1\times10^{-10}[/tex]

Therefore the sun is 1.391016 time the size of an atom at this scale.