Answer:
The point P reflected across the lines x=3 and y=2.
Step-by-step explanation:
From the given graph it is clear that the coordinates of P are (0,0) and the coordinates of E are (6,4).
[tex]P(0,0)\rightarrow E(6,4)[/tex] .... (1)
If the origin reflected across the line x=a then
[tex](0,0)\rightarrow (2a,0)[/tex]
If the origin reflected across the line y=b, then
[tex](0,0)\rightarrow (0,2b)[/tex]
If the origin reflected across the line x=a and y=b, then
[tex](0,0)\rightarrow (2a,2b)[/tex] .... (2)
From (1) and (2) we get
[tex]2a=6\Rightarrow a=3[/tex]
[tex]2b=4\Rightarrow b=2[/tex]
The value of a is 3 and the value of b is 2. Therefore the point P reflected across the lines x=3 and y=2.
