As you can see by the Comments under the question,
Afscrappermomp5lzxc and I had some private correspondence
after I asked for additional information. It turns out that all three
resistors are in series in her circuit, and we can now go ahead
and solve the problem.
In a series circuit, there's only one possible path for the current
to follow on its trip from one side of the battery to the other side.
The electrical ' current ' is the same at every point in the circuit,
and also, all of the resistors in the circuit act as if there was only
ONE resistor, with a value equal to the SUM of all the individual ones.
So this particular circuit looks like it has one single resistor across
the battery, and its resistance is (4.0Ω + 3.2Ω + 3.4Ω) = 10.6 Ω .
That's wonderful. Now it's a piece-'o-cake to find the current.
One form of Ohm's Law says ...
Current = (voltage) / (resistance)
Current = (5 volts) / (10.6 Ω) = 0.472 Amperes (rounded)
