in right triangle abc with the right angle c , sinA = 2x + 0.1 and cosB = 4x - 0.7 determine and state the value of X . explain your answer

If the right angle is C, then that must mean that B and A are not right angles and they are opposite of each other (in the triangle). So, if you can imagine such a triangle, you will easily see that cos(B) = sin(A). Based on this, we can:
[tex]4x-0.7=2x+0.1[/tex]
[tex]4x=2x+0.8[/tex]
[tex]2x=0.8[/tex]
[tex]x = 0.4[/tex]

So, x = 0.4, and the answer is explained above.

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swapnalimalwadeVT swapnalimalwadeVT · Answer 2 · 2022-05-23T15:42:40+02:00

In the given right angle triangle C the value of the x is equal to 0.4.

In right triangle abc with the right angle c , sinA = 2x + 0.1 and cosB = 4x - 0.7

If the right angle is C, then that must mean that B and A are not right angles and they are opposite of each other (in the triangle). So, if you can imagine such a triangle, you will easily see that.

What will we get after the comparing equation?

cos(B) = sin(A)

Based on this, we can

4x-0.7=2x+0.8

4x=2x+0.8

2x=0.8

x=0.4

Therefore, x = 0.4, and the answer is explained above.

To learn more about the triangle visit:

https://brainly.com/question/2437195

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