Respuesta :
The temperature of a cup of coffee has been reduced by 71 °C.
The temperature of the cup decreases from 95.0 °C. So the coffee absorbs heat. That heat was absorbed by the spoon, which initially was at a lower temperature i.e 25 °C. Assuming that all heat transfer was between the spoon and the coffee, with no heat “lost” to the surroundings, then heat given off by coffee = -heat taken in by spoon, or:
[tex]\rm q_c_o_f_f_e_e\;=\;-q_s_p_o_o_n[/tex]
[tex]\rm m_1[/tex]c[tex]\Delta[/tex]T = [tex]\rm m_2[/tex]c[tex]\Delta[/tex]T
Let the change in temperature be x
180 [tex]\times[/tex] c [tex]\times[/tex] (95 - x) = 45 [tex]\times[/tex] c [tex]\times[/tex] (25 + x)
17100 - 180x = 1125 + 45x
17100 - 1125 = 45x + 180x
15975 = 225x
x = 71 °C.
The reduction in the temperature of cup of coffee will be 95 - 71 °C
The temperature of a cup (180 g) of coffee at 95 °C be reduced to 24 °C.
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