You have a gas at 453 mm Hg with a volume of 700 mL and a temperature of 25 °C, what will the temperature of the gas be, if you change the pressure to 278 mm Hg and a volume of 1200 mL?
The temperature of a the gas is calculated using combined gas law formula that is P1V1/T1 = P2V2/T2 P1 = 453mmhg V1= 700ml T1 = 25 + 273 = 298k P2 = 278 mmhg V2 = 1200ml T2= ?
T2 is therefore = T1 P2V2/p1V1 = 298 x278 x1200/ 453 x 700 = 313.5 K
