If the pressure is 100,000 Pa, the volume is 2 m3, R is 8.314, and the temperature is 100 K, which is closest to the number of moles (n) of gas?

A. 1
B. 240
C. 400
D. 20

Respuesta :

We can solve the problem by using the ideal gas law:

[tex] pV=nRT [/tex]

where

[tex] p=100000 Pa [/tex] is the gas pressure

[tex] V=2 m^3 [/tex] is the gas volume

n is the number of moles

[tex] R=8.314 J/mol K [/tex] is the gas constant

[tex] T=100 K [/tex] is the absolute temperature of the gas


By rearranging the equation and substituting the numbers, we find the number of moles of the gas:

[tex] n=\frac{pV}{RT}= \frac{(100000 Pa)(2 m^3)}{(8.314 J/mol K))(100 K)}=240.5 mol [/tex]


so, the correct answer is

B. 240