A chemist reacts 8.85 g of iron with an excess of hydrochloric acid to form hydrogen gas and iron(II) chloride. Calculate the theoretical yield and the percent yield of hydrogen if 0.27 g of H2 are collected.


TY = g H2 PY = %

Respuesta :

  The  theoretical  yield  and  percent  yield  of  hydrogen  if  0.27  g  of  H2   collected  is   calculated  as follows

write the  reaction   equation

that  is  Fe  +  Hcl  = H2  + FeCl2

calculate  moles  of  Fe = mass/molar  mass  =  8.85 g/56   g/mol  =0.158 moles

by  use  mole  ratio  between Fe  : H2  which  is  1:1  the  theoretical moles  of hydrogen =  0.158moles
the  theoretical mass  is  therefore =   moles x  molar mass
= 0.158 mol x2g/mol  =0.316   grams

% mass =  actual  mass/   theoretical  mass  x 100

= 0.27/0.316 x100  =  85.4 %