Suppose you just received a shipment of eleven televisions. three of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?

Hello!

You have to first find the percentage of the tv's are defective

3/11 = 0.27

27% of the tvs are defective

the probability of one of the tv's working is 8/11

the probability of the second tv working is 7/10

You multiply these together

8/11 * 7/10 = 28/55

There is a 28 out of 55 chance both tvs work

There is a 3/11 probability that one of the tvs does not work

Hope this helps!

Answer Link

mkryukova19 mkryukova19 · Answer 2 · 2018-04-14T06:03:18+02:00

mkryukova19 mkryukova19

14-04-2018

1) 11-3= 8 TV work
8/11 - probability 1st TV works
7/10 -probability 2nd TV works
8/11*7/10=28/55 that both TV work

2)3/11 first TV does not work
8/10 second TV works
3/11*8/10 = 12/55 that at least one does not work

Answer Link

Suppose you just received a shipment of eleven televisions. three of the televisions are defective. if two televisions are randomly​ selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not​ work?

Respuesta :

Otras preguntas

Suppose you just received a shipment of eleven televisions. three of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?