If 0° < θ < 90°, is sin θ equal to cos (90° – θ), and for what reason?
A) No, because angles measuring θ and 90° – θ are supplements.
B) No, because angles measuring θ and 90° – θ are complements.
C) Yes, because angles measuring θ and 90° – θ are supplements.
D) Yes, because angles measuring θ and 90° – θ are complements.

Respuesta :

Answer:

Option D. Yes, because angles measuring [tex](\theta)[/tex]  and [tex](90\°-\theta)[/tex]  are complements

Step-by-step explanation:

we know that

Two angles are complementary if their sum is equal to [tex]90[/tex] degrees

and

If two angles are complementary, then the function sine of one angle is equal to the function cosine of the other angle

therefore

In this problem

[tex](\theta)+(90\°-\theta)=90\°[/tex]

so

[tex](\theta)[/tex]  and [tex](90\°-\theta)[/tex] -----> are complementary angles

hence

[tex]sin(\theta)=cos(90\°-\theta)[/tex]

The correct option is [tex]\boxed{{\mathbf{option D}}}[/tex] .

Further explanation:

Given:

It is given that [tex]\sin\theta=\cos\left({90-\theta }\right)[/tex]  if [tex]0^\circ <\theta<90^\circ[/tex] .

Step by step explanation:

Step 1:

Complementary angles are those two angles whose sum is equal to [tex]90^\circ[/tex] .

The given angles are [tex]\theta{\text{ and 90}}-\theta[/tex] .

Now find the sum of the given angles to check whether these angle are complementary or not.

  [tex]\theta+90-\theta =90[/tex]

It can be seen that the sum of the angles is [tex]90^\circ[/tex] .  

Therefore, [tex]\theta{\text{ and 90}}-\theta[/tex] are complementary angles.

Step 2:

We know that the sine of any acute angle is equal to the cosine of its complement angle.

Therefore, [tex]\sin\theta=\cos\left({90-\theta }\right)[/tex]  as [tex]\theta{\text{ and 90}}-\theta[/tex]  are complementary angles.

Now consider all the options.

Option A:  No, because angles measuring [tex]\theta{\text{ and 90}}-\theta[/tex]  are supplements.

The supplementary angles are those two angles whose sum is equal to [tex]180^\circ[/tex] .

As it has been proved that [tex]\theta{\text{ and 90}}-\theta[/tex]  are complementary angles.

Thus, option A is not correct.

Option B: No, because angles measuring [tex]\theta{\text{ and 90}}-\theta[/tex]  are complements.

It has been proved that [tex]\sin\theta=\cos\left({90-\theta}\right)[/tex]  as [tex]\theta{\text{ and 90}}-\theta[/tex]  are complementary angles.

Thus, option B is not correct.

Option C: Yes, because angles measuring [tex]\theta{\text{ and 90}}-\theta[/tex]  are supplements.

This option is also not correct.

Option D: Yes, because angles measuring [tex]\theta{\text{ and 90}}-\theta[/tex]  are complements.

It has been proved that [tex]\sin\theta=\cos\left({90-\theta}\right)[/tex]  as [tex]\theta{\text{ and 90}}-\theta[/tex]  are complementary angles.

Thus, option D is correct.

Learn more:  

  • Learn more about the function is graphed below https://brainly.com/question/9590016
  • Learn more about the symmetry for a function https://brainly.com/question/1286775
  • Learn more about midpoint of the segment https://brainly.com/question/3269852

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Trignometry

Keywords: sine function, cosine function, complementary angles, supplementary angles, measurement, angles, acute angle, complement, sum of the angles, supplements.