Respuesta :
NH4Br is a strong electrolyte. In water, it dissociates 100% to give:
NH4Br (s)---> NH4+ (aq) + Br- (aq)
Br- is the anion of the strong acid HBr, so it is neutral.
NH4+ is the cation of the weak base NH3. It donates a proton to water producing an ACIDIC solution.
The equilibrium reaction that takes place is:
NH4+(aq) + H2O ---> H3O+(aq) + NH3(aq)
NH4Br (s)---> NH4+ (aq) + Br- (aq)
Br- is the anion of the strong acid HBr, so it is neutral.
NH4+ is the cation of the weak base NH3. It donates a proton to water producing an ACIDIC solution.
The equilibrium reaction that takes place is:
NH4+(aq) + H2O ---> H3O+(aq) + NH3(aq)
The net ionic equation is
[tex]\rm NH_4+(aq) + H_2O --- > H_3O+(aq) + NH_3(aq)[/tex]
What is an equilibrium reaction?
An equilibrium reaction is the reaction in which the reactants remain stable after the reaction.
NH₄Br is a strong electrolyte, is dissociating 100%
[tex]\rm NH_4Br (s)--- > NH_4+ (aq) + Br^- (aq)[/tex]
Br- is the anion of strong acid HBr
NH₄⁺ is the cation of the weak base NH₃
It donates a proton to water, producing an acidic solution.
Thus, The net ionic equation is
[tex]\rm NH_4+(aq) + H_2O --- > H_3O+(aq) + NH_3(aq)[/tex]
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