Answer:
[tex](2x-7)(2x+7)[/tex]
Step-by-step explanation:
Use the identity rule:
[tex](a^2-b^2) = (a-b)(a+b)[/tex]
To factor the given expression:
[tex]4x^2-49y^2[/tex]
we can write this as:
[tex](2x)^2-(7y)^2[/tex]
Apply the identity rule we have;
[tex](2x-7)(2x+7)[/tex]
Therefore, the completely factor of the given expression is, [tex](2x-7)(2x+7)[/tex]