The energy of a single photon is given by
[tex]E=hf[/tex]
where
[tex]h=6.6 \cdot 10^{-34} Js[/tex] is the Planck constant
f is the frequency of the wave (of the photon)
In our problem, the radio wave has a frequency of [tex]f=4.40 \cdot 10^8 Hz[/tex], so if we put this value into the previous formula, we can find the energy of a single photon of this electromagnetic wave:
[tex]E=hf=(6.6 \cdot 10^{-34} Js)(4.40 \cdot 10^8 Hz)=2.9 \cdot 10^{-25} J[/tex]
