The molality of a solution that contains 63.0 g HNO3 in 0.500kg H2O is 2 M.
Molarity is the number of solutes dissolved in a given a solvent, while the two exist in the solution.
molarity = moles / volume (liters)
molecular mass of HNO3 = 63 g/mol
moles = 63/63 = 1 mole
volume = mass/density
volume = (0.5 kg) / (1000 kg/m³)
volume = 5 x 10⁻⁴ m³ = 0.5 L
m = n/L
m = 1/0.5 L
m = 2 M
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