Let the ages be s, a and d.
Then s+a = 32, s + d = 54, and d+a = 34.
Here you have 3 equations in 3 unknowns, so you have enuf info to solve this problem.
Start with s+d=54 and subtract s+a=32. We get d-a=54-32 = 22.
d - a = 22
d + a = 34 Combine these 2 equations:
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2d = 56, d = 28. If d-a=22, then 28-a=22, and a = 6.
Find s. Since s+a=32, s+6=32, and s=26.
Sharon is 26 years old, Darrin is (34-6), or 28, and Aaron is 6 years old.
The diff between father's and son's ages is 28-6 = 22.
