Alright, so, I'm so happy cause I got 100%, but this is how you solve the problem.
Since we have the info, here's the formula for it: [tex] \frac{sinA}{a} = \frac{sinB}{b} [/tex]
Since it doesn't have ΔABC, We'll use the acronyms of their names to make it easier. ΔMBK. We're solving for the length of K to M.
[tex] \frac{sinB}{b} = \frac{sinK}{k} [/tex]
[tex] \frac{sin50}{b} = \frac{sin63}{14} [/tex]
The substitutions for these are the numbers that represent them and the b is the length between K and M.
[tex]14sin50 = bsin63
[/tex]
[tex] \frac{14sin50}{sin63} = \frac{bsin63}{sin63} [/tex]
[tex]12.0365248879...=b[/tex]
b = 12.0
Hope this helps you. :D
