286 ml water is needed to dilute 1 liter of 90% isopropyl alcohol to make a 70% alcohol solution.
So, option C is correct one.
Calculation,
1 L = 1000 ml water contain 90% isopropyl alcohol
So, X ml of water required to make a 70% alcohol solution = ?
Formula used: [tex]M_{1}V_{1} = M_{2} V_{2}[/tex]
0.9 ×1000 = 0.7 × X
X = 0.9 ×1000/0.7 = 1285.71 ml
1285.71 ml - 1000 ml = 285.71 ml ≈ 286 ml
Thus, you would add 285.71 ml of water to 1000 ml or 1 L of 90% isopropyl alcohol to make a 70% alcohol solution.
The solution is amount of solute with less concentration or is low as compare to solvent is called dilute solution.
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