Respuesta :

intercept  ⇒ when f(x) = 0

f(x) = 3x² - 12x - 1

3x² - 12x - 1 = 0

[tex]x = \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a} [/tex]

[tex]x = \dfrac{-(-12)\pm \sqrt{(-12)^2 - 4(3)(-1)} }{2(3)} [/tex]

[tex]x = 4.08 \ or \ x= -0.08[/tex]

Answer: The two x-intercepts are (4.08, 0) and (-0.08, 0)


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