I'm not sure about finding 'three areas', but the formula to calculate the area of a trapezium is
[tex] \frac{a + b}{2} h[/tex]
a and b are the parallel widths of the trapezium, and h is the height. Using this, we can answer your question by substituting the given information:
[tex]area \: = \frac{9 + 20}{2} \times 15 \\ = \frac{29}{2} \times 15 \\ = 14.5 \times 15 \\ = 217.5[/tex]
Therefore, the area of the trapezium pictured is 217.5m^2