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kenmyna
  The number  of  aluminium  atoms     that  are  in  319  g  of  Al2S3  is  calculated   as  follows

find  the total  moles  of  Al2s3

=moles  =  mass/molar =  319 g  /  150  g/mol  =  2.13  moles
since  there  are  two  atom   of  Al  in  Al2S3  the  moles  of  Al  =  2  x    2.13  = 4.26 moles

by  use  of  Avogadro  law  constant    1 mole  =  6.02  x10^23    atoms
what   about  4.26  moles  of  Al

=  4.26  moles   x(  6.02  x10^23) =  2.56  x10^  24  atoms

Answer : The number of aluminium atoms are, [tex]25.65\times 10^{23}[/tex]

Explanation : Given,

Mass of [tex]Al_2S_3[/tex] = 319 g

Molar mass of [tex]Al_2S_3[/tex] = 150 g/mole

First we have to calculate the moles of [tex]Al_2S_3[/tex].

[tex]\text{Moles of }Al_2S_3=\frac{\text{Mass of }Al_2S_3}{\text{Molar mass of }Al_2S_3}=\frac{319g}{150g/mole}=2.13moles[/tex]

Now we have to calculate the number of atoms of aluminium.

In [tex]Al_2S_3[/tex], there are 2 atoms of aluminium and 3 atoms of sulfur.

As, 1 mole of [tex]Al_2S_3[/tex] contains [tex]2\times 6.022\times 10^{23}[/tex] number of aluminium atoms.

As, 2.13 mole of [tex]Al_2S_3[/tex] contains [tex]2.13\times 2\times 6.022\times 10^{23}=25.65\times 10^{23}[/tex] number of aluminium atoms.

Therefore, the number of aluminium atoms are, [tex]25.65\times 10^{23}[/tex]

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