The area of a room is 396 square feet. The length is (x + 8) feet and the width is (x + 4) feet. Find the dimensions of the room.


You only need to find the length and width.

Respuesta :

umm6
L:18ft
W:22ft
Hope it helps

Answer:

Area of rectangle (A) is given by:

[tex]A = lw[/tex]

where, l is the length and w is the width of the rectangle.

As per the statement:

The area of a room is 396 square feet.

The length is (x + 8) feet and the width is (x + 4) feet.

⇒A = 396 square feet , l = (x+8) feet and w = (x+4) feet

Substitute these given values we have;

[tex]396 = (x+8)(x+4)[/tex]

⇒[tex]396 = x^2+4x+8x+32[/tex]

Combine like terms;

⇒[tex]396 = x^2+12x+32[/tex]

Subtract 32 from both sides we have;

[tex]364 = x^2+12x[/tex]

or

[tex]x^2+12x-364 =0[/tex]

⇒[tex]x^2+26x-14x-364 = 0[/tex]

⇒[tex]x(x+26)-14(x+26)=0[/tex]

⇒[tex](x+26)(x-14) = 0[/tex]

By zero product property we have;

x+26 = 0 or x-14 = 0

⇒x = -26 and x = 14

Since, side cannot be in negative.

⇒x = 14

then;

l = x+8 = 14+8 = 22 feet

w = x+4 = 14+4 = 18 feet

Therefore, the dimensions of the room are:

l = 22 feet and w = 18 feet